All but Two
A man describes his daughters, saying, “They are all blonde but two; all brunette but two; and all redheaded but two.” How many daughters does the man have?
The man has 3 daughters; one blonde, one brunette, and one redhead.
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A man describes his daughters, saying, “They are all blonde but two; all brunette but two; and all redheaded but two.” How many daughters does the man have?
The man has 3 daughters; one blonde, one brunette, and one redhead.
I have a spine but no other bones.
I wear a jacket but no other clothes.
What am I?
The answer is BOOK.
What coin does this sum spell?
What number does this sum spell?
DOLL + ARROW + BOAT – ROW BOAT = DOLLAR
FOWL – OWL + ORANGE – RANGE + URCHIN – CHIN = FOUR
You have 12 balls, 11 of which have the same weight. The remaining one is defective and either heavier or lighter than the rest. You can use a balance scale to compare weights in order to find which is the defective ball and whether it is heavier or lighter. How many measurement do you need so that will be surely able to do it?
It is easy to see that if we have more than 9 balls, we need at least 3 measurements. We will prove that 3 measurements are enough for 12 balls.
We place 4 balls on each side of the scale. Let balls 1, 2, 3, 4 be on the right side, and balls 5, 6, 7, 8 on the left side.
CASE 1. The scale does not tip to any side. For the second measurement we place on the left side balls 1, 2, 3, 9 and on the right side balls 4, 5, 10, 11.
If the scale again does not tip to any side, then the defective ball is number 12 and we can check whether it is heavier or lighter with our last measurement.
If the scale tips to the left side, then either the defective ball is number 9 and is heavier, or it is number 10/11 and is lighter. We measure up balls 10 and 11 against each other and if one of them is lighter than the other, then it is the defective one. If they have the same weight, then ball 9 is the defective one.
If the scale tips to the right side, the procedure is similar.
CASE 2. Let the scale tip to the left side during the first measurement. This means that either one of the balls 1, 2, 3, 4 is defective and it is heavier, or one of the balls 5, 6, 7, 8 is defective and it is lighter. Clearly, balls 9, 10, 11, 12 are all genuine. Next we place balls 1, 2, 5, 6 on one side and balls 3, 7, 9, 10 on the other side.
If the scale tips to the left, then either one of the balls 1, 2 is defective and it is heavier, or ball 8 is defective and lighter. We just measure up balls 1 and 2 against each other and find out which among the three is the defective one.
If the scale tips to the right, the procedure is similar.
If the scale does not tip to any side, then either the defective ball is 4 and it is heavier, or the defective ball is 8 and it is lighter. We just measure up balls 1 and 4 against each other and easily find the defective ball.
A teacher enters the classroom and sees on the first row two students sitting next to each other, looking completely identical. She asks them if they are twins, but the students simultaneously reply that they are not. After checking in the records, the teacher furthermore discovers that the two children have the same mother and father. What is the explanation?
The students are three of a triplet.
Lose me once ill come back stronger, lose me twice ill leave forever. What am I?
The answer is TOOTH.
Based on the logic of the first four pairs of words and shapes, figure out what the fifth word is.
The first letter is P if the shapes are circles and B if the shapes are squares.
The second letter is A if the shapes are green and E if the shapes are red.
The third letter is N if the number of shapes is 2 and R if the number of shapes is 3.
The fourth letter is T if the shapes are arranged vertically and S if the shapes are arranged horizontally.
Therefore, the last word should be BENT.
The horse got $18, the the bee got $27, the duck got $9, and the spider got $36. How much did the snake get?
Every animal got $4.50 for every leg it has. Therefore, the snake got nothing.
The city has 49 districts that vote for blue, yellow, or purple as shown in the grid. Seven electoral regions are drawn up to elect a city council. Each region consists of seven districts and each region will elect one councilor. Can you gerrymander the map so that blue will win the majority?
The solution is shown below.
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